Question

How do you solve using the quadratic formula `17x^2 = 12x`?

Answer 1

To use the quadratic formula (which, by the way is not the easiest way to do this) first convert into the standard form
`ax^2+bx+c =0`

`17x^2=12x`
`17x^2-12x+0=0`

The quadratic formula for roots is
`x = (-b+-sqrt(b^2-4ac))/(2a)`

`x=(12+-sqrt((-12)^2- 4(17)(0)))/(2(17))`

`x= 12/17`
or
`x=0`

Answer 2

Write it as:
`17x^2-12x=0`
this is now in the form: `ax^2+bx+c=0`
With:
`a=17`
`b=-12`
`c=0`
That can be used in the quadratic formula to get your two Real solutions (if possible) for `x` as:
`x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`
Try by yourself substituting values (you should get two real values).