# How do you solve using the quadratic formula 17x^2 = 12x ?

Apr 29, 2015

To use the quadratic formula (which, by the way is not the easiest way to do this) first convert into the standard form
$a {x}^{2} + b x + c = 0$

$17 {x}^{2} = 12 x$
$17 {x}^{2} - 12 x + 0 = 0$

The quadratic formula for roots is
$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$x = \frac{12 \pm \sqrt{{\left(- 12\right)}^{2} - 4 \left(17\right) \left(0\right)}}{2 \left(17\right)}$

$x = \frac{12}{17}$
or
$x = 0$

Apr 29, 2015

Write it as:
$17 {x}^{2} - 12 x = 0$
this is now in the form: $a {x}^{2} + b x + c = 0$
With:
$a = 17$
$b = - 12$
$c = 0$
That can be used in the quadratic formula to get your two Real solutions (if possible) for $x$ as:
${x}_{1 , 2} = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
Try by yourself substituting values (you should get two real values).