How do you solve using the quadratic formula #2x^2 + 5x - 3 = 0#?

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Answer 1 · 2015-05-14T20:57:48

#2x^2+5x-3 = 0# is of the form #ax^2+bx+c = 0# with #a=2#, #b=5# and #c=-3#.

The quadratic formula tells us that this has solutions:

#x = (-b +- sqrt(b^2-4ac))/(2a)#

#= (-5 +- sqrt(5^2-4*2*(-3))) / (2*2)#

#= (-5 +- sqrt(25+24))/4#

#= (-5 +- sqrt(49))/4#

#= (-5 +- 7)/4#

In other words, #x = 1/2# or #x = -3#