Question

How do you solve using the quadratic formula `6x^2 - 6x = x + 9`?

Answer 1

Rewrite `6x^2-6x = x+9`
into the standard `ax^2+bx+c=0` form:

`6x^2-7x-9=0`

The quadratic formula for roots is
`x = (-b+-sqrt(b^2-4ac))/(2a)`

with the given example
`x= (7+-sqrt(49+216))/12`

`= (7+-sqrt(265))/12`