# How do you solve using this equation (2x^2 = 40) using the square root property?

We first divide both sides by $2$ to get ${x}^{2} = 20$
$\sqrt{20} \mathmr{and} - \sqrt{20}$ give $20$ when squared.
So ${x}_{1 , 2} = \pm \sqrt{20} = \pm 2 \sqrt{5}$ (two answers)