# How do you solve v^2/25-1=11?

Oct 30, 2016

$v$ is approximately $\pm 17.32$ or $\pm \sqrt{300}$

#### Explanation:

To solve for $v$ perform the following operations to keep the equation balanced while isolating $v$:

${v}^{2} / 25 - 1 + 1 = 11 + 1$

${v}^{2} / 25 = 12$

$\left({v}^{2} / 25\right) 25 = 12 \cdot 25$

${V}^{2} = 300$

$\sqrt{{V}^{2}} = \pm \sqrt{300}$

$v = \pm 17.32$