Question

How do you solve `(w-10)^3 + 32=0` where `w` is a real number?

Answer 1

`w=10+root(3)(-32)`

Explanation:

`(w-10)^3+32=0`

`(w-10)^3=-32`

`w-10=root(3)(-32)`

`w=10+root(3)(-32)`