# How do you solve (x-1)^2=4?

Sep 11, 2016

$x = - 1 , x = 3$

#### Explanation:

Since we have a squared value on the left we require to take the $\textcolor{b l u e}{\text{square root}}$ of both sides of the equation.

$\sqrt{{\left(x - 1\right)}^{2}} = \pm \sqrt{4}$

$\Rightarrow x - 1 = \pm 2$

solve: $x - 1 = + 2 \Rightarrow x = 2 + 1 = 3$

solve: $x - 1 = - 2 \Rightarrow x = - 2 + 1 = - 1$