How do you solve #(x - 1)^2 = 9#?
x1= 4 and x2=-2
x^2 - 2x*1 +1^2 = 9
since this is a quadratic equation it has to be equal to 0, so:
we can solve this in two ways: the first way is to find the factors of x^2-2x-8 and the second one is to solve it by using the quadratic formula.
Let me factorize it.
In order for this to be equal zero:
x-4=0 => x=4
x+2=0 => x=-2
The quadratic equation has always two roots or two solutions. Consequently, x1= 4 and x2=-2.
Use the golden rule of Algebra: What you do on one side must be done on the other side also
Take the square root of both sides (
Solve for both
#color(blue)( ul bar |x=(4,-2)|#