How do you solve #(x+1)/(x-1)=2/(2x-1)+2/(x-1)#?
We have an equation,
For simplicity, which you might find to your liking, I'll be taking
Now, we have two terms, one on either side of the equation to have the same denominator, being
so what I'll be doing is that I'll subtract on both sides by
Since the terms on the left-hand side already had the same denominator, I already grouped them together.
By solving the sum on the numerator of the left-hand side, we get
Now, what is the numerator of the left-hand side similar to? If you go back up to the top of the answer, you'll see that I equated
So that makes the left-hand side of the equation as
Now, we know that
I'm sure it'll be easy to find the answer now.