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# How do you solve (x-1)/(x+1)= (-3x)/(2x+2) + x/(6x+6)?

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#### Explanation

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#### Explanation:

I want someone to double check my answer

1
dseah Share
Jun 18, 2018

$x = \frac{6}{14} \mathmr{and} x = - 1$

#### Explanation:

Need to get denominator same for the two additions

$\frac{- 3 x \left(6 x + 6\right) + x \left(2 x + 2\right)}{\left(2 x + 2\right) \left(6 x + 6\right)}$

$\frac{- 18 {x}^{2} - 16 x}{\left(2 x + 2\right) \left(6 x + 6\right)}$

$\frac{- 8 x \left(2 x + 2\right)}{\left(2 x + 2\right) \left(6 x + 6\right)}$

$\frac{- 8 x}{6 x + 6} = \frac{x - 1}{x + 1}$

$- 8 x \left(x + 1\right) = \left(6 x + 6\right) \left(x - 1\right)$

$- 8 {x}^{2} - 8 x = 6 {x}^{2} - 6$

$0 = 14 {x}^{2} + 8 x - 6$

$0 = \left(14 x - 6\right) \left(x + 1\right)$

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