# How do you solve x=11+2y and 7x+2y=13 using substitution?

x=3 ; y= -4
Substituting $x = 11 + 2 y$ on equation we get $7 \left(11 + 2 y\right) + 2 y = 13 \mathmr{and} 14 y + 2 y = 13 - 77 \mathmr{and} 16 y = - 64 \mathmr{and} y = - 4$; Putting y=-4 we get $x = 11 + 2 \cdot \left(- 4\right) = 3$[Ans]