How do you solve #x/12-4=20#?

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Answer 1 · 2018-03-05T07:56:16

See a solution process below:

First, add #color(red)(4)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#x/12 - 4 + color(red)(4) = 20 + color(red)(4)#

#x/12 - 0 = 24#

#x/12 = 24#

Now, multiply each side of the equation by #color(red)(12)# to solve for #x# while keeping the equation balanced:

#color(red)(12) xx x/12 = color(red)(12) xx 24#

#cancel(color(red)(12)) xx x/color(red)(cancel(color(black)(12))) = 288#

#x = 288#