How do you solve #|x + 13| = 2x + 1#?

Question

1639 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-10T15:10:18

Socratic graph is pointer to the solution x = 12/

graph{|x+13|-2x-1 [11.5, 12.5, -.5, .5]}

The graph for the function reveals x = 12 as the solution.

Algebraically,

When #x >=-13, x+13 = 2x + 1#,

giving a valid solution.#x = 12 > -13#.

When #x <=-13, -(x+13) = 2x + 1#,

giving invalid solution.#x =-(1 4)/3 > -13#.