# How do you solve x^2-10x+18=0 using the quadratic formula?

Mar 31, 2017

You simply put the coefficients of the equation into the formula and solve it algebraically.

#### Explanation:

For $a {x}^{2} + b x + c = 0$, the values of x which are the solutions of the equation are given by: x = ​(−b±√[​b​^2​​−4ac])/(2a)

In this case, a = 1, b = -10 and c = 18

x = ​(−(-10) ± sqrt[(-10^​2​ ​− 4*1*18]))/(2*1)

x = ​(10 ± sqrt[(100 – 72)])/2 ; x = ​(10 ± sqrt[28])/2

x = ​(10 ± 5.29)/2

x = 2.35, and x = 7.645

CHECK: 7.645^2 – 10*7.645 + 18 = 0 ; 58.446 – 76.45 + 18 = 0 ; 0 = 0 correct.