# How do you solve x^2-10x+25=0?

${x}^{2} - 10 x + 25 = 0$
${x}^{2} - 5 x - 5 x + 25 = 0$
$x \left(x - 5\right) - 5 \left(x - 5\right) = 0$
${\left(x - 5\right)}^{2} = 0$
$\implies x = 5 , 5$