How do you solve $x^{2} + 10 x = 39$ $x^2+10x=39$ by completing the square?

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How do you solve $x^{2} + 10 x = 39$ $x^2+10x=39$ by completing the square?

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Answer 1 · 2016-05-28T23:41:54

-13 and 3

Explanation:

$x^{2} + 10 x = 39$ $x^2 + 10x = 39$
$x^{2} + 10 x + 25 = 39 + 25 = 64$ $x^2 + 10x + 25 = 39 + 25 = 64$
${(x + 5)}^{2} = 64$ $(x + 5)^2 = 64$
$(x + 5) = \pm 8$ $(x + 5) = +- 8$
$x = - 5 \pm 8$ $x = - 5 +- 8$
The 2 real roots are:
x = -13 and x = 3.

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How do you solve $x^{2} + 10 x = 39$ $x^2+10x=39$ by completing the square?

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How do you solve x2+10x=39x^2+10x=39 by completing the square?

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How do you solve $x^{2} + 10 x = 39$ $x^2+10x=39$ by completing the square?