# How do you solve x^2+10x=39 by completing the square?

May 28, 2016

-13 and 3

#### Explanation:

${x}^{2} + 10 x = 39$
${x}^{2} + 10 x + 25 = 39 + 25 = 64$
${\left(x + 5\right)}^{2} = 64$
$\left(x + 5\right) = \pm 8$
$x = - 5 \pm 8$
The 2 real roots are:
x = -13 and x = 3.