How do you solve $x^2-10x+8=0$ by completing the square?

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Answer 1 · 2015-04-29T17:34:09

Write it as:
$x^2-10x=-8$ add and subtract $25$ ;
$x^2-10x+25-25=-8$
$(x-5)^2-25=-8$
$(x-5)^2=17$
$x-5=+-sqrt(17)$
$x_(1,2)=5+-sqrt(17)$

How do you solve x^2-10x+8=0x^2-10x+8=0 by completing the square?