How do you solve #x^2-10x+8=0# by completing the square?

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Answer 1 · 2015-04-29T17:34:09

Write it as:
#x^2-10x=-8# add and subtract #25#;
#x^2-10x+25-25=-8#
#(x-5)^2-25=-8#
#(x-5)^2=17#
#x-5=+-sqrt(17)#
#x_(1,2)=5+-sqrt(17)#