Question

How do you solve `x^2 - 121`?

Answer 1

`x=11, x=-11`

Explanation:

Using the difference of squares, which states that

`(x^2-a^2)=(x+a)(x-a)`:

`(x^2-121)=0`

`(x+11)(x-11)=0`

`x=11, x=-11`