# How do you solve x^2+12x-64=0 using the quadratic formula?

Jul 2, 2015

Identify a, b, and c in your equation. Then substitute the values into the quadratic equation. Solve for $x$.

#### Explanation:

${x}^{2} + 12 x - 64 = 0$

a=1; b=12; $c = - 64$

$x = \frac{- 12 \pm \sqrt{{12}^{2} - \left(4 \cdot 1 \cdot - 64\right)}}{2 \cdot 1}$ =

$x = \frac{- 12 \pm \sqrt{144 + 256}}{2}$ =

$x = \frac{- 12 \pm \sqrt{400}}{2}$ =

$x = \frac{- 12 \pm 20}{2}$

$x = \frac{- 12 + 20}{2}$ =

$x = \frac{8}{2}$ =

$x = 4$

$x = \frac{- 12 - 20}{2}$ =

$x = - \frac{32}{2}$ =

$x = - 16$

$x = 4 , - 16$