How do you solve #x^2-13x+36=0#?

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Answer 1 · 2016-03-31T00:30:29

#x_1=9#
#x_2=4#

Let us start from the given quadratic equation

#x^2-13x+36=0#
Solution by factoring

#(x-4)(x-9)=0#

Equate each factor to zero to solve for the roots

#x-4=0#
#x_1=4#

#x-9=0#
#x_2=9#

God bless...I hope the explanation is useful.