# How do you solve x^2-13x+36=0?

${x}_{1} = 9$
${x}_{2} = 4$

#### Explanation:

Let us start from the given quadratic equation

${x}^{2} - 13 x + 36 = 0$
Solution by factoring

$\left(x - 4\right) \left(x - 9\right) = 0$

Equate each factor to zero to solve for the roots

$x - 4 = 0$
${x}_{1} = 4$

$x - 9 = 0$
${x}_{2} = 9$

God bless...I hope the explanation is useful.