# How do you solve x^2 - 14x + 49 = 3?

Oct 30, 2015

 x= 7±sqrt(3)

#### Explanation:

You make the equation equal zero so you subtract three from both sides.

${x}^{2} - 14 x + 46 = 0$
You can't factor it so you can either complete the square or use the quadratic formula

x=(-b±sqrt(b^2-4ac))/(2a)

$a = 1 , b = - 14 , c = 46$
Insert that and you get

 x=(-(-14)±sqrt((-14)^2-4(1)(46)))/(2(1))

x= (14±sqrt(196-184))/(2)

x= (14±sqrt(12))/(2)

Factor $\sqrt{12}$ to sqrt(4*3 then square root the 4 to 2 making $2 \sqrt{3}$

 x= (14±2sqrt(3))/(2)
Simplify

 x= 7±sqrt(3)