# How do you solve x^2-16/25=0?

Oct 25, 2016

$x = + \frac{4}{5} , x = - \frac{4}{5}$

#### Explanation:

There are two different methods we can use.

1. Factorise as Difference of squares

${x}^{2} - \frac{16}{25} = 0$

$\left(x + \frac{4}{5}\right) \left(x - \frac{4}{5}\right) = 0$

Either factor could be equal to 0.

$x + \frac{4}{5} = 0 \text{ } \rightarrow x = - \frac{4}{5}$

$x - \frac{4}{5} = 0 \text{ } \rightarrow x = + \frac{4}{5}$

$2.$ Find the square root.

${x}^{2} = \frac{16}{25}$

$x = \pm \sqrt{\frac{16}{25}}$

$x = + \frac{4}{5} , x = - \frac{4}{5}$