How do you solve #x^2 - 16x = - 64 #?

1 Answer
Don't Memorise
Jun 15, 2015

#color(green)( x = 8#

Explanation:

#x^2-16x + 64 = 0#
We can first factorise this expression and then proceed towards finding the solution.

Factorising by splitting the middle term

#x^2-16x + 64 =x^2-8x - 8x + 64 #

#x^2-8x - 8x + 64= x (x-8) - 8(x-8) #

# =color(green)((x-8)(x-8)#
So the solution for the expression will be:
# x- 8 = 0#
#color(green)( x = 8#

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