How do you solve # (x + 2)^2 = 36#?

1 Answer
Apr 15, 2018

Answer:

#x=-8" or "x=4#

Explanation:

#color(blue)"take the square root of both sides"#

#sqrt((x+2)^2)=+-sqrt36larrcolor(blue)"note plus or minus"#

#rArrx+2=+-6#

#"subtract 2 from both sides"#

#rArrx=-2+-6#

#rArrx=-2-6=-8" or "x=-2+6=4#

#color(blue)"As a check"#

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

#x=-8to(-8+2)^2=(-6)^2=36#

#x=4to(4+2)^2=6^2=36#

#rArrx=-8" or "x=4" are the solutions"#