# How do you solve (x + 2)/2 = (y + 18)/4 and x/3 = (2y + 4)/6?

Jul 6, 2018

$x = 12 , y = 10$

#### Explanation:

Multiplying the second equation by $3$

$x = \frac{3}{6} \cdot \left(2 y + 4\right) = \frac{2 y + 4}{2} = y + 2$

and multiplying the fist equation by $4$

$2 \left(x + 2\right) = y + 18$
multiplying out

$2 x + 4 = y + 18$
adding $- 4$

$2 x = y + 14$
plugging the equation above ($x = y + 2$)

in this equation

$2 y + 4 = y + 14$

adding $- 4$ and $- y$

$y = 10$

so $x = 12$