How do you solve #x^2+21x+110=0#?
You can solve this both by factoring and Quadratic formula
If you have a problem with factoring
Watch this video:
Factor the equation
Now we can say
This is a Quadratic equation (in form
Now we have two solutions
#color(blue)( :.ul bar |x=-10,-11|#
(x + 10)(x + 11)
Use the new AC Method to factor trinomials (Socratic Search).
Find 2 numbers knowing sum (b = 21) and product (c = 11).
Since ac > 0, they have same sign.
Compose factor pairs of (c = 110) --> ...(5, 22)(10, 11). This sum is 21 = b. Then the numbers are 10 and 11.
Answer: y = (x + 10)(x + 11)