How do you solve #x^2+2ax = b^2-a^2# by factoring?

1 Answer
Aug 11, 2015

Answer:

#x=-a-b#
or
#x=-a+b#

Explanation:

Given #x^2+2ax = b^2 -a^2#

#rArr##color(white)("XXXX")#x^2+2ax+a^2 = b^2#

Factoring the left side:
#rArr##color(white)("XXXX")##(x+a)^2 = b^2#

Taking the square root:
#rArr##color(white)("XXXX")##x+a = +-b#

Subtracting #a# from both sides:
#rArr##color(white)("XXXX")##x = -a+-b#