Question

How do you solve `x^2 - (2sqrt3)x - 45 = 0`?

Answer 1

`x=5sqrt3 and x= -3sqrt3`

Explanation:

`x^2-(2sqrt3)x-45=0 or x^2-(2sqrt3)x +(sqrt3)^2 -3-45=0 or (x-sqrt3)^2=48 or (x-sqrt3) = +- sqrt48 or (x-sqrt3) = +-4sqrt3 or x = sqrt3+4sqrt3= 5sqrt3`and `x = sqrt3-4sqrt3 or x= - 3sqrt3`[Ans]