# How do you solve x^2 - (2sqrt3)x - 45 = 0?

$x = 5 \sqrt{3} \mathmr{and} x = - 3 \sqrt{3}$
${x}^{2} - \left(2 \sqrt{3}\right) x - 45 = 0 \mathmr{and} {x}^{2} - \left(2 \sqrt{3}\right) x + {\left(\sqrt{3}\right)}^{2} - 3 - 45 = 0 \mathmr{and} {\left(x - \sqrt{3}\right)}^{2} = 48 \mathmr{and} \left(x - \sqrt{3}\right) = \pm \sqrt{48} \mathmr{and} \left(x - \sqrt{3}\right) = \pm 4 \sqrt{3} \mathmr{and} x = \sqrt{3} + 4 \sqrt{3} = 5 \sqrt{3}$and $x = \sqrt{3} - 4 \sqrt{3} \mathmr{and} x = - 3 \sqrt{3}$[Ans]