# How do you solve x^2 - 2x + 1 = 4  by completing the square?

The square is already complete on the left side and it is ${\left(x - 1\right)}^{2}$. Therefore problem is now to solve for x the equation ${\left(x - 1\right)}^{2}$=4. Take square root on both sides to get x-1=$\pm$2. This gives x=3, -1.