How do you solve $x^{2} - 2 x + 1 = 4$ $x^2 - 2x + 1 = 4$ by completing the square?

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How do you solve $x^{2} - 2 x + 1 = 4$ $x^2 - 2x + 1 = 4$ by completing the square?

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Answer 1 · 2015-06-02T14:13:07

Answer is x=3, -1

The square is already complete on the left side and it is ${(x - 1)}^{2}$ $(x-1)^2$ . Therefore problem is now to solve for x the equation ${(x - 1)}^{2}$ $(x-1)^2$ =4. Take square root on both sides to get x-1= $\pm$ $+-$ 2. This gives x=3, -1.

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How do you solve $x^{2} - 2 x + 1 = 4$ $x^2 - 2x + 1 = 4$ by completing the square?

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How do you solve $x^{2} - 2 x + 1 = 4$ $x^2 - 2x + 1 = 4$ by completing the square?