# How do you solve #x^2 - 2x + 10 = 0#?

##### 2 Answers

#### Answer:

#### Explanation:

#"the equation is in standard form "color(white)(x)ax^2+bx+c=0#

#"with "a=1,b=-2" and "c=10#

#"there are no whole number values which allow us to"#

#"factor the quadratic"#

#"check the value of the "color(blue)"discriminant"#

#•color(white)(x)Delta=b^2-4ac#

#b^2-4ac=(-2)^2-(4xx1xx10)=4-40=-36#

#"since "Delta<0" then roots are complex"#

#"to calculate use the "color(blue)"quadratic formula"#

#•color(white)(x)x=(-b+-sqrt(b^2-4ac))/(2a)#

#rArrx=(2+-sqrt(-36))/2=(2+-6i)/2#

#rArrx=1+-3i#

#### Answer:

**Solution:**

#### Explanation:

It has complex roots.

Solution: