How do you solve #x^2+2x-13=2#?
1 Answer
May 20, 2018
Explanation:
#"express in standard form "color(white)(x)ax^2+bx+c=0#
#"subtract 2 from both sides"#
#rArrx^2+2x-15=0#
#"the factors of - 15 which sum to + 2 are + 5 and - 3"#
#rArr(x+5)(x-3)=0#
#"equate each factor to zero and solve for x"#
#x+5=0rArrx=-5#
#x-3=0rArrx=3#
