# How do you solve -x^2 - 2x + 2 =0 using the quadratic formula?

Oct 15, 2015

$x = - 3 , x = 1$

#### Explanation:

$- {x}^{2} - 2 x + 2 = 0$

$a {x}^{2} + b x + c = 0$

a is the constant with x to the power 2.
b is the constant with x to the power 1
c is the constant.

In the given Equation:

a = -1
b = -2
c = 3

$\frac{- b \pm \sqrt{{b}^{2} - 4 \left(a\right) \left(c\right)}}{2 \left(a\right)}$
$\frac{- \left(- 2\right) \pm \sqrt{{\left(- 2\right)}^{2} - 4 \left(- 1\right) \left(3\right)}}{2 \left(- 1\right)}$
$\frac{2 \pm \sqrt{\left(4 + 12\right)}}{-} 2$
$\frac{2 \pm \sqrt{16}}{-} 2$
$\frac{2 \pm 4}{-} 2$
$\frac{2 + 4}{-} 2 , \frac{2 - 4}{-} 2$
$\frac{6}{-} 2 , - \frac{2}{-} 2$
$x = - 3 , x = 1$