Question

How do you solve `-x^2 - 2x + 2 =0` using the quadratic formula?

Answer 1

`x = -3, x = 1`

Explanation:

`-x^2 -2x +2 = 0`

Standard Quadratic Equation:

`ax^2 + bx + c = 0`

a is the constant with x to the power 2.
b is the constant with x to the power 1
c is the constant.

In the given Equation:

a = -1
b = -2
c = 3

Standard Quadratic Formula:

`(-b+-sqrt(b^2 - 4(a)(c))) / (2(a))`
`(-(-2) +-sqrt((-2)^2 - 4(-1)(3))) / (2(-1))`
`(2+-sqrt((4 + 12)) ) / -2`
`(2+-sqrt(16)) / -2`
`(2+-4) / -2`
`(2 + 4) / -2, (2 - 4) / -2`
`6 / -2, -2 / -2`
`x = -3, x = 1`