How do you solve #x^2+2x=3#?

1 Answer
Jun 28, 2016

Answer:

#x=-3# or #x=1#

Explanation:

#x^2+2x=3#

Implies
#color(white)("XXX")x^2+2x-3=0#

which can be factored as
#color(white)("XXX")(x+3)(x-1)=0#

which, in turn, implies
either
#color(white)("XXX")x+3=0 color(white)("XX")rarrcolor(white)("XX")x=-3#
or
#color(white)("XXX")x-1=0 color(white)("XX")rarrcolor(white)("XX")x=1#

(As always you should substitute these values into the original equation to verify the result).