How do you solve #x-2/3=-4/5#?

1 Answer
Feb 7, 2017

Answer:

See the entire solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(15)# to eliminate the fractions while keeping the equation balanced:

#color(red)(15)(x - 2/3) = color(red)(15) xx -4/5#

#(color(red)(15) xx x) - (color(red)(15) xx 2/3) = cancel(color(red)(15))3 xx -4/color(red)(cancel(color(black)(5)))#

#15x - (cancel(color(red)(15))5 xx 2/color(red)(cancel(color(black)(3)))) = -12#

#15x - 10 = -12#

Next, add #color(red)(10)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#15x - 10 + color(red)(10) = -12 + color(red)(10)#

#15x - 0 = -2#

#15x = -2#

Now, divide each side of the equation by #color(red)(15)# to solve for #x# while keeping the equation balanced:

#(15x)/color(red)(15) = -2/color(red)(15)#

#(color(red)(cancel(color(black)(15)))x)/cancel(color(red)(15)) = -2/15#

#x = -2/15#