# How do you solve (x+2)/3+(x-3)/4=1?

Mar 22, 2018

$x = \frac{13}{\text{7}}$

#### Explanation:

$\frac{x + 2}{\text{3}}$ + $\frac{x - 3}{\text{4}}$ = 1

$\frac{\left(x + 2\right) \left(4\right)}{\text{3 (4)}}$ + $\frac{\left(x - 3\right) \left(3\right)}{\text{4 (3)}}$ = 1/1

$\frac{\left(x + 2\right) 4 + \left(x - 3\right) 3}{\text{12}}$ = 1

$\frac{4 x + 8 + 3 x - 9}{\text{12}}$ = 1

$\frac{7 x - 1}{\text{12}}$ = 1 (multiply both sides with 12)

7x - 1 = 12

7x = 13

x = $\frac{13}{\text{7}}$