# How do you solve #x^2+3x-10=0#?

##### 1 Answer

Aug 1, 2015

#### Answer:

Solve y = x^2 + 3x - 10 = 0

Ans: 2 and -5

#### Explanation:

Find 2 numbers knowing sum (-3) and product (-10).

Factor pairs of (-10) -> (-2, 5). This sum is 3 = b. Then the opposite numbers **2** and **-5** are the real roots.