Question

How do you solve `x^2+3x-180=0`?

Answer 1

12 and - 15

Explanation:

`y = x^2 + 3x - 180 = 0.`
The 2 real roots have opposite signs (ac < 0).
Factor pairs of (-180) --> ...(10, -18)(12, -15). This last sum is (-3 = -b). There for the 2 real roots are: 12 and - 15.