# How do you solve x^2 - 3x - 23 = 5?

Aug 7, 2015

Solve $y = {x}^{2} - 3 x - 23 = 5$

Ans: -4 and 7

#### Explanation:

$y = {x}^{2} - 3 x - 28 = 0$
Find 2 numbers p and q, knowing sum (-b = 3) and product (c = -28).
p and q have opposite signs. (Rule of sign).
Factor pairs of (-28) --> (-2, 14)(-4, 7). This sum is 3 = -b.
Then, the 2 real roots are : $- 4$ and $7.$