How do you solve #x^2 - 3x + 27 = 8x - 3#?
1 Answer
Mar 29, 2016
#x=8#
#x=3#
Explanation:
Given -
#x^2-3x+27=8x-3#
Bring all terms to right hand side
#x^2-3x+27-8x+3=0#
#x^2 -11x+24=0#
#x^2-3x-8x+24=0#
#x(x-3)-8(x-3)=0#
#(x-8)(x-3)=0#
#x-8=0#
#x=8#
#x-3=0#
#x=3#
