How do you solve x^2 - 3x + 27 = 8x - 3?

Mar 29, 2016

$x = 8$
$x = 3$

Explanation:

Given -

${x}^{2} - 3 x + 27 = 8 x - 3$
Bring all terms to right hand side
${x}^{2} - 3 x + 27 - 8 x + 3 = 0$
${x}^{2} - 11 x + 24 = 0$
${x}^{2} - 3 x - 8 x + 24 = 0$
$x \left(x - 3\right) - 8 \left(x - 3\right) = 0$
$\left(x - 8\right) \left(x - 3\right) = 0$
$x - 8 = 0$
$x = 8$
$x - 3 = 0$
$x = 3$