How do you solve #x^2 - 3x - 3 = -5 # using the quadratic formula?

1 Answer
Apr 24, 2018

Answer:

#x = 2, x = 1#

Explanation:

The quadratic formula is always fun! Let's start with it.
#(-b+-sqrt(b^2-(4ac)))/(2a)#

The variables, b a, and c represent the coefficients to the terms you possess in the original equation. #a# representing the coefficient attached to the #x^2# term, #b# representing the coefficient attached to the #x# term, and #c# representing the constant, which is, in your case, 2.

So, with this in hand, we can rewrite the formula to obtain:
#(-(-3)+-sqrt((-3)^2-(4(1)(2))))/(2(1))#

So you simplify to obtain
#(3+-sqrt(1))/(2(1))#

So you get #2# and #1# from + and - the square root, respectively.