How do you solve x^2 - 3x - 3 = -5  using the quadratic formula?

Apr 24, 2018

$x = 2 , x = 1$

Explanation:

$\frac{- b \pm \sqrt{{b}^{2} - \left(4 a c\right)}}{2 a}$
The variables, b a, and c represent the coefficients to the terms you possess in the original equation. $a$ representing the coefficient attached to the ${x}^{2}$ term, $b$ representing the coefficient attached to the $x$ term, and $c$ representing the constant, which is, in your case, 2.
$\frac{- \left(- 3\right) \pm \sqrt{{\left(- 3\right)}^{2} - \left(4 \left(1\right) \left(2\right)\right)}}{2 \left(1\right)}$
$\frac{3 \pm \sqrt{1}}{2 \left(1\right)}$
So you get $2$ and $1$ from + and - the square root, respectively.