# How do you solve #x^2 + 3x - 4 = 0# graphically and algebraically?

##### 1 Answer

Jul 22, 2016

#x=1#

#x=-4#

#### Explanation:

Given -

#x^2+3x-4=0#

Algebraic Solution

#x^2-x+4x-4=0#

#x(x-1)+4(x-1)=0#

#(x-1)(x+4)=0#

#x=1#

#x=-4#

If you take the above equation as a function as

#y=x^2+3x-4#

One Solution is

#(1, 0)#

Another solution is

#(-4,0)#

To have a graphic solution, You have identify a range of

values for

Its vertex is given by -

#x=(-b)/(2xxa)=(-3)/(2 xx1)=-3/2#

Now take four values above and below

Find the corresponding

Plot all the values. Those co-ordinates where the curve cuts the x-axis is the graphic solution to the problem.