How do you solve #( x - 2) - ( 3x + 4) = 2#?

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Answer 1 · 2018-04-03T11:51:42

#x=-4#

#(x-2)-(3x+4)=2#

Remove the brackets:

#x-2-3x-4=2#

#-2x-6=2#

#2x=-8#

#x=-4#

Answer 2 · 2018-04-03T11:54:12

#x=-4#

#(x-2)-(3x+4)=2#
#(x-2)-3x-4=2#
#-2x-6=2#
Adding six on both sides,
#-2x=8#
Dividing by -2 on both sides,
#x=-4#

Answer 3 · 2018-04-03T11:54:48

#x= -4#

Firstly, we open the bracket. Therefore

#x-2-3x-4=2#

Now, taking the like terms together

#x-3x-2-4-2=0#

Solving the equation

#-2x-8=0#

#-2x=8#

#x=8/-2#

#x=-4#