# How do you solve x^2 + 3x - 40 = 0?

The answers for x^2+3x−40=0 are -8 and 5.
For this problem, we are able to factor. Since 8 and 5 are both factors of 40, and since 8-5=3, we will use 8 and 5 in our binomial equation: $\left(x + 8\right) \left(x - 5\right) = 40$. Just to prove that this is correct, let's multiply the two together: ${x}^{2} - 5 x + 8 x - 40 = {x}^{2} + 3 x - 40$. From here, we can use the zero product property to get our answers: $x + 8 = 0 , x - 5 = 0$. Subtract 8 from the first equation and subtract 5 from the second equation to get our answers, -8 and 5.