How do you solve #x^2 -3x = -7#?

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Answer 1 · 2015-08-11T17:14:28

The solutions are:
#color(green)(x = ((3)+sqrt(-19))/(2#

#color(green)(x = ((3)-sqrt(-19))/(2#

#x^2−3x+7=0#

The equation is of the form #color(blue)(ax^2+bx+c=0# where:

#a=1, b=-3, c=7#

The Discriminant is given by:
#Delta=b^2-4*a*c#

# = (-3)^2-(4*1*7)#

# = 9-28=-19#

The solutions are found using the formula
#x=(-b+-sqrtDelta)/(2*a)#

#x = (-(-3)+-sqrt(-19))/(2#

The solutions are:
#color(green)(x = (3+sqrt(-19))/(2#

#color(green)(x = (3-sqrt(-19))/(2#