How do you solve #x^2 – 3x = 7x – 2#?

1 Answer
Aug 5, 2015

Answer:

#x= 5+-sqrt(23)#

Explanation:

#x^2-3x = 7x -2#

is equivalent (subtract #(7x-2)# from both sides) to
#x^2-10x+2 = 0#

Using the quadratic formula for roots
#color(white)("XXXX")##x= (-b+-sqrt(b^2-4ac))/(2a)#
which in this case gives
#color(white)("XXXX")##x= (10+-sqrt(10^2-4(1)(2)))/(2(1)#

#color(white)("XXXX")##color(white)("XXXX")##= 5+-sqrt(23#