# How do you solve x^2+ 4 = 0?

Apr 14, 2018

$x = \pm 2 i \text{ }$

#### Explanation:

${x}^{2} + 4 = 0 \text{ }$ subtract 4 on both sides to get

${x}^{2} = - 4 \text{ }$ Take the square root of both sides to get

$x = \pm 2 i \text{ }$

Apr 14, 2018

$x = \pm 2 i$

#### Explanation:

For this, you need a concept of imaginary numbers

${x}^{2} + 4 = 0$

$\Rightarrow {x}^{2} + 4 - 4 = 0 - 4$

(Subtracting $4$ from both sides)

$\Rightarrow {x}^{2} = - 4$

$\Rightarrow x = \sqrt{- 4}$

$\Rightarrow x = \sqrt{- 1 \times 4}$

$\Rightarrow x = \pm 2 \sqrt{- 1}$

(The value of $\sqrt{- 1}$ is $i$ )

$\Rightarrow x = \pm 2 i$

Hope this helps :)

Apr 14, 2018

No real solution

#### Explanation:

${x}^{2} + 4 = 0$

Start by subtracting $4$ from both sides

${x}^{2} + 4 - 4 = 0 - 4$

${x}^{2} = - 4$

Now we can take square root

$x = \pm \sqrt{- 4}$

Thus,

No real solutions