Question

How do you solve `x^2+4=5x`?

Answer 1

Make it equal to 0.
Factorise, then let each factor in turn be equal to 0.
`x = 4, x = 1`

Explanation:

`x^2 - 5x + 4 = 0 " "` make a quadratic equation = 0

`(x - 4)(x - 1) = 0" "` factors of 4 which add to 5 are 4 x 1

If `x - 4 = 0 rArr x = 4" "` if `x - 1 = 0 rArr x = 1`