How do you solve $x^{2} - 4 x = 0$ $x^2 - 4x = 0$ by factoring?

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Answer 1 · 2015-08-12T06:31:57

The solutions are:
$x = 0, x = 4$ $color(blue)(x=0,x=4$

$x^{2} - 4 x = 0$ $x^2-4x=0$

Here $x$ $color(blue)(x$ is common to both the terms of the expression

$x (x - 4) = 0$ $color(blue)(x)(x-4)=0$

Now we equate each of the two factors to zero, to obtain the solutions.

$x = 0$ $color(blue)(x=0$
$x - 4 = 0, x = 4$ $x-4=0, color(blue)(x=4$

How do you solve x^2 - 4x = 0x2−4x=0 x^2 - 4x = 0 by factoring?