How do you solve #x^2 = 4x + 12#?
We take the coefficient on the
Since our goal is to rewrite our equation in the form of
We replace our
Now, we are looking for two numbers whose product gives
We can see that
Taking the square root of both sides yields
So our solutions are
-2 and 6
Find 2 numbers (real roots), that have opposite signs, knowing the sum (-b = 4) and the product (c = -12). They make the factor pair
(-2, 6) --> sum (4) and product (-12).
2 real roots: -2, and 6