# How do you solve x^2+4x-12=0?

Nov 17, 2016

$\left(x + 6\right) \left(x - 2\right) = 0$ gives

$x = 2 \text{ or } x = - 6$

#### Explanation:

${x}^{2} + 4 x - 12 = 0$

Find factors of 12 which subtract (because of the MINUS) to make 4.

The correct factors will be $6 \mathmr{and} 2$

Their signs must be DIFFERENT (because of the MINUS 12)

The greater must be positive (because of the PLUS 4)

$\left(x + 6\right) \left(x - 2\right) = 0$

Now either of the two factors can be 0, to give the product of 0.

$x + 6 = 0 \text{ } \rightarrow x = - 6$

$x - 2 = 0 \text{ } \rightarrow x = 2$